By James W. Nilsson, Susan Riedel
For sophomore point, one- or two-semester Introductory Circuit research or Circuit conception classes taught in electric or desktop Engineering Departments. mentioned by way of IEEE Spectrum as an "up and coming vintage within the box of circuits,"Electric Circuits is the main commonly used introductory circuits textbook. This revision of either textual content and strong supplementations package deal beneficial properties an elevated emphasis on scholar and teacher evaluate, a redesigned paintings software, a brand new four-color structure, and plentiful new or revised difficulties all through. The 7th version keeps the pursuits that experience made this article a best-seller: 1) to construct an figuring out of innovations and ideas explicitly by way of past studying; 2) to stress the connection among conceptual knowing and challenge fixing techniques; three) to supply scholars with a robust starting place of engineering practices
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Additional resources for Electric Circuits. Solution Manual
5 [a] Yes, independent voltage sources can carry whatever current is required by the connection; independent current source can support any voltage required by the connection. 6 Write the two KCL equations, summing the currents leaving the node: KCL, top node: 25A − 20A − 5A = 0A KCL, bottom node: − 25A + 20A + 5A = 0A Write the three KVL equations, summing the voltages in a clockwise direction: KVL, left loop: KVL, right loop: − v25 + v20 = 0 60V − 100V − v5 − v20 = 0 Problems 2–13 60V − 100V − v5 − v25 = 0 KVL, outer loop: Note that since v5 , v20 , and v25 are not speciﬁed, we can choose values that satisfy the equations.
The simpliﬁed circuit is shown below: [c] The 600 Ω, 200 Ω, and 300 Ω resistors are in series. 4 i2 = 8 A, is = 12 A [a] From Ex. 5 Always work from the side of the circuit furthest from the source. Remember that the current in all series-connected circuits is the same, and that the voltage drop across all parallel-connected resistors is the same. 6 Always work from the side of the circuit furthest from the source. Remember that the current in all series-connected circuits is the same, and that the voltage drop across all parallel-connected resistors is the same.
Since the power is positive, the sources are absorbing 200 W of power, or developing −200 W of power. 7 Write the two KCL equations, summing the currents leaving the node: KCL, top node: − 30A − i8 + 10A = 0A KCL, bottom node: 30A + i8 − 10A = 0A Note that the value i8 = −20A satisﬁes these two equations. Write the three KVL equations, summing the voltages in a clockwise direction: KVL, left loop: − v30 − 16V + 8V = 0 KVL, right loop: − 10V + v10 − 8V = 0 KVL, outer loop: − 16V − 10V + v10 − v30 = 0 Note that v30 = −8V and v10 = 18V satisfy the three KVL equations.
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