By Xingming Sun, Alex Liu, Han-Chieh Chao, Elisa Bertino
This quantity set LNCS 10039 and 10040 constitutes the refereed post-conference court cases of the second one foreign convention on Cloud Computing and safety, ICCCS 2016, held in Nanjing, China, in the course of July 29-31, 2016.
The ninety seven papers of those volumes have been rigorously reviewed and chosen from 272 submissions. The papers are geared up in topical sections akin to: details Hiding, Cloud Computing, Cloud safety, IOT purposes, Multimedia purposes, Multimedia protection and Forensics.
Read or Download Cloud Computing and Security: Second International Conference, ICCCS 2016, Nanjing, China, July 29-31, 2016, Revised Selected Papers, Part II PDF
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Additional info for Cloud Computing and Security: Second International Conference, ICCCS 2016, Nanjing, China, July 29-31, 2016, Revised Selected Papers, Part II
Obviously, we can get OLP in polynomial time by solving LP(2) optimally. However, either xi,j or xj should be equal to 0 or 1 in the task assignment model, which means a value between 0 to 1 is meaningless. Thus, OLP is often not a feasible solution of IP(1). To solve this problem, we need to design a mechanism to convert the OLP to a feasible solution of IP(1). 2 A Near-Optimal Solution for the Optimal Task Assignment Problem To convert OLP to a feasible solution of IP(1), we need to select the allocation relationships which satisfy 0 < xi,j < 1 in OLP , and set them equal to 1.
3. Next in Sect. 4, the simulation and performance evaluations on CACA-UAN are given. Finally, we conclude the paper and discuss future works in Sect. 5. CACA-UAN: A Context-Aware Communication Approach 2 39 Related Work and Challenges The underwater sensor networks have been greatly developed in the military and civil areas and simultaneously enable a broad range of applications, including tracking, navi‐ gating and monitoring. For enhancing the service quality of these applications, reliable and eﬃcient communication technologies can be developed to supporting the data trans‐ mission.
As a result, a0 is used as the group key. Step 3. Distribution of the Key Now, the random number a0 has been assigned to the group key (K) by the server. After that, the server distributes the K to all members of the group as follows: • According to Shamir’s SS, f(x) divides the secret K into N + 1 shares: Si = f(mi) (i = 1, 2, 3, …, N + 1) where mi(i = 1, 2, 3, …, N + 1) are random numbers over GF(p). Meanwhile, the server calculates a hash value: AUTH = hash(K, Ts1, S1, S2, S3, …, SN+1) that be used for the authentication, where Ts1 is the timestamp of AUTH.
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